已知如图所示两个正方形并排摆放,边长分别是8cm、6cm,求阴影部分面积?
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分享交流一下我的解题思路:
连接CG
S△CGH=S△ACH-S△ACG
=½×8×14-½×8×8
=24
S△CGH=½×CH×DG=7×DG
24=7×DG
DG=24/7
EG=6—24/7=18/7
S阴=(8+24/7)×8÷2+(6+18/7)×6÷2
=320/7+180/7
=500/7
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欢迎大家评论区留下宝贵的解题思路,共同探讨学习[比心][比心]
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